Solved Are The Following Decays Possible If Not Why Not Chegg No, because in alpha decay, the atomic number stays the same, and the mass number of the daughter nucleus should be less than that of the parent nucleus. are the following decays possible? if not, why not? yes. no, because in alpha decay, the mass number is reduced by four, not two. no, because in alpha decay, the atomic number is reduced by. In this problem, we are given four different decays and we need to determine whether these decays are possible or not and mention the justification. in order to solve this problem, we need to calculate the mass number and the atomic number of the two sides of the equation and compare them. if they are equal, the decay is a possible decay.
Solved 5 Are The Following Decays Possible If Not Why Cheggођ Here the total mass number dropped down by one, but the number of protons rose by one. this means that the initial nucleus lost two neutrons and gained a proton. the final electron conserves the charge, but the reaction is not possible. it looks like beta decay, but the mass number should not change, we should just trade one neutron for one proton. Video answer: so in this question we are asked to complete a few grammatical reactions. the first reaction that's given to us is 1 31 i star, meaning that it's it's an excited state and this gives us…. Once again, we use conservation of atomic and mass number. \begin {align*} &238=236 4 \\ &94=92 2 \end {align*} 238 = 236 4 94 = 92 2. in this case the atomic number is indeed conserved but the mass number is not and we conclude that this reaction is \textbf {not possible} not possible. getting to the last reaction we have. A positron is the opposite of a β particle, it is \(\ce{^0 { 1}e}\), the mass number will not change but the atomic number will decrease by 1. answer e. electron capture has the same effect on the nucleus as positron emission: the atomic number is decreased by one and the mass number does not change.
Solved Are The Following Decays Possible If Not Why Not Chegg Once again, we use conservation of atomic and mass number. \begin {align*} &238=236 4 \\ &94=92 2 \end {align*} 238 = 236 4 94 = 92 2. in this case the atomic number is indeed conserved but the mass number is not and we conclude that this reaction is \textbf {not possible} not possible. getting to the last reaction we have. A positron is the opposite of a β particle, it is \(\ce{^0 { 1}e}\), the mass number will not change but the atomic number will decrease by 1. answer e. electron capture has the same effect on the nucleus as positron emission: the atomic number is decreased by one and the mass number does not change. This problem has been solved! you'll get a detailed solution that helps you learn core concepts. question: are the following decays possible? if not, why not? physics. are the following decays possible? if not, why not? physics. here’s the best way to solve it. Nuclear reaction energy, such as released in α decay, can be found using the equation e = (Δm)c2. we must first find Δm, the difference in mass between the parent nucleus and the products of the decay. this is easily done using masses given in appendix a. solution. the decay equation was given earlier for 239pu; it is.
Solved Are The Following Decays Possible If Not Why Not Chegg This problem has been solved! you'll get a detailed solution that helps you learn core concepts. question: are the following decays possible? if not, why not? physics. are the following decays possible? if not, why not? physics. here’s the best way to solve it. Nuclear reaction energy, such as released in α decay, can be found using the equation e = (Δm)c2. we must first find Δm, the difference in mass between the parent nucleus and the products of the decay. this is easily done using masses given in appendix a. solution. the decay equation was given earlier for 239pu; it is.
Solved Is The Following Decay Possible Chegg
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